Exception Handling in JAVA

Exception Handling:-

  • Each and every exception is considered as an object.
  • If there is any exception in running programming then program receives appropriate object or an exception from JRE.
  • After receiving an object of that exception it is responsibility of the program to handle that exception.
  • If the program is unable to handle an exception then that exception is forwarded to the default exception handle in java.
  • Default exception handler of java prints an exception message on the screen and terminates the program abnormally.
  • To avoid this abnormal termination we have to handle that exception in our program.
  • After handling an exception in the program our program can continue for remaining instructions.

e.g.

void gun()

{

int no;

no=10/0;

}

void fun()

{

gun();

}

public static void main(String args[])

{

fun();

}

Output:-

gun :: ArithmaticException, divideByZeroException

fun

main

  • This is a stack trace of our program. In this program we get an exception inside a gun function and JRE prints each and every function call from that function by unwinding the stack frame.
  • In this case exception is not handled due to which it is forwarded to the default exception handler.

 

Exception Handling

 

Try block:-

  • All the statements written inside a try block are observed by the JRE for the exceptions.
  • If there is some exception inside a try then JRE throws an object of that exception and that object is accepted by appropriate catch block.
  • Inside a catch block we have to write a code for handling that exception.
  • After handling the exception inside the catch block our program can continue its exception successfully.
  • If there is no appropriate catch block inside the program then that exception is forwarded to its super class exception catch code and default exception handler of java.

e.g.

class demo

{

int i,j,k;

i=10;

j=0;

fun()

{

try{

System.out.println(“inside a try block”);

k=i/j;

}catch(ArithmaticException e)

{

System.out.println(“inside catch block.”);

}

System.out.println(“After the catch block.”);

}

}

class hello

{

public static void main(String args[])

{

demo d = new demo();

d.fun();

System.out.println(“after calling fun.”);

}

}

Output:-

inside try block

inside catch block

after the catch block

after calling fun

  • If the try block contains an exception code then the code after exceptional instruction is not executed because the control is directly transfer to the catch block.
  • Therefore the line after exceptional instruction is not executed.

Multiple catch or single try block:-

  • We can write multiple catch blocks for single try block.
  • The appropriate catch block is evaluated depend on the exception.
  • If we have to provide catch block then the flow of that catch block must be in decreasing order of their class hierarchy.
  • Means a sub class exception is handled first before derived class exception.
  • If there is an exception inside a catch block then JRE scans each and every catch block in the top to bottom order.
  • If any catch block is matched with that exception then control is not passed by remaining catch block.

e.g.

try{

int no=10/0;

}catch(Exception e)

{

System.out.println(“inside first catch block.”);

}

catch(ArithmaticException e)

{

System.out.println(“inside second catch block.”);

}

Output:-

Error

  • Because in java unreachable code is considered as an error.
  • In our example, second catch block is an unreachable code.
  • But if we swap hat catch block then program runs successfully.
  • Because ArithmaticException catch block can successfully handled divideByZeroException.

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Sourabh Bhunje

Sourabh Bhunje, B.E. IT from Pune University. Currently Working at Techliebe. Professional Skills: Programming - Software & Mobile, Web & Graphic Design, Localization, Content Writing, Sub-Titling etc. http://techliebe.com/about-us

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